Mar 17, 2015 · It can't be possible to replace captured uppercase or lowercase letter with the letter according to the type of letter captured through regex alone. But it can be possible through language built-in functions + regex. In php, i would do like.
var s2 = s.replace(/your complex regex/g, "#$&#"); The back-reference $& brings in the entire match. If you want to match "abc" in any case: var s2 = s.replace(/abc/ig, "#$&#"); If you only want to bring in part of a larger pattern, you can refer to it by its group number: var s2 = s.replace(/some (part) of a string/ig, "#$1#");
You must use groups with parentheses (group of regex) Do the Regex to find/Search the numerical digits and spaces. The group here will be the digits as it is surrounded in parenthesis Run a replace regex ops. Replace spaces for a dash but keep the numbers or digits in each line
What the regex basically means is: match the digits in front of the first dot as group 1 and everything after it as group 2 (but only if it ends with mp3) Show activity on this post. I tested with vscode. You must use groups with parentheses (group of regex) Do the Regex to find/Search the numerical digits and spaces.
You can insert the text matched by the regex or capturing groups simply by using the regex-related variables in your replacement text. Perl’s case conversion escapes also work in replacement texts. The most common use is to change the case of an interpolated variable. \U converts everything up to the next \L or \E to uppercase.
Some applications can insert the text matched by the regex or by capturing groups converted to uppercase or lowercase. The Just Great Software applications allow you to prefix the matched text token \0 and the backreferences \1 through \99 with a letter that changes the case of the inserted text.
Dim input As String = "$17.43 €2 16.33 £0.98 0.43 £43 12€ 17" Dim replacement As String = "$2" Dim rgx As New Regex(pattern) Dim result As String = rgx.Replace(input, replacement) Console.WriteLine("Original String: '{0}'", input) Console.WriteLine("Replacement String: '{0}'", result) End Sub End Module ' The example displays the following output: ' Original String: …
@Noj I added them in case you wanted to extend the regex with some other stuff. The paranthesis around the variable ss turn it into a capturing group. Since this one is the first capturing group ((?i) is not a capturing group), I accessed it with $1 afterwards.$0 accesses the whole match, so for example if you used "(?i)"+ss+" something" as your regex, something …
Nov 17, 2011 · will preserve case, because it reuses the matched text. Note that i is the case insensitivity flag, and g means it will match every occurrence, rather than just the first as would happen without the g flag. For a pretty good overview …
May 19, 2022 · When the regex (? i) (helló) (wórld) matches HeLlÓ WóRlD the replacement text \U \l $1 \E \L \u $2 becomes hELLÓ Wórld. Literal text is also affected. \U $1 Dear $2 becomes HELLÓ DEAR WÓRLD. Perl’s case conversion works in regular expressions too. But it doesn’t work the way you might expect.
This can be done easily using regular expressions. In a substitute command, place \U or \L before backreferences for the desired output. Everything after \U, stopping at \E or \e, is converted to uppercase. Similarly, everything after \L, stopping at \E or \e, is converted to lowercase.
Mar 17, 2022 · Open the search and replace pane Ctrl+R. Make sure that is selected in the search field. In the search field enter the search pattern. In the replace field, depending on what you want to achieve, enter one of the following syntax: \l changes a character to lowercase until the next character in the string. For example, Bar becomes bar.
The syntax for the REGEXP_REPLACE function in Oracle is: REGEXP_REPLACE ( string, pattern [, replacement_string [, start_position [, nth_appearance [, match_parameter ] ] ] ] ) Parameters or Arguments string The string to search. It can be CHAR, VARCHAR2, NCHAR, NVARCHAR2, CLOB, or NCLOB. pattern The regular expression matching information.